0=9x^2-24x+x

Solution for 0=9x^2-24x+x equation:

0=9x^2-24x+x

We move all terms to the left:

0-(9x^2-24x+x)=0

We add all the numbers together, and all the variables

-(9x^2-24x+x)=0

We get rid of parentheses

-9x^2+24x-x=0

We add all the numbers together, and all the variables

-9x^2+23x=0

a = -9; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-9)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-9}=\frac{-46}{-18}
=2+5/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-9}=\frac{0}{-18}
=0
$